Solve the product (2t-2)(2t+3)

 Exercise

$\left(2t-2\right)\left(2t+3\right)$

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Multiply the single term $2t+3$ by each term of the polynomial $\left(2t-2\right)$

$2t\left(2t+3\right)-2\left(2t+3\right)$

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Multiply the single term $2t$ by each term of the polynomial $\left(2t+3\right)$

$4t\cdot t+6t-2\left(2t+3\right)$

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When multiplying two powers that have the same base ($t$), you can add the exponents

$4t^2+6t-2\left(2t+3\right)$

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Multiply the single term $-2$ by each term of the polynomial $\left(2t+3\right)$

$4t^2+6t-4t-6$

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Combining like terms $6t$ and $-4t$

$4t^2+2t-6$

$4t^2+2t-6$

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