Exercise
$\left(4y^2+1\right)\left(4y^2-1\right)$
Step-by-step Solution
Learn how to solve special products problems step by step online. Simplify the product of conjugate binomials (4y^2+1)(4y^2-1). The sum of two terms multiplied by their difference is equal to the square of the first term minus the square of the second term. In other words: (a+b)(a-b)=a^2-b^2.. The power of a product is equal to the product of it's factors raised to the same power. Calculate the power 4^2. Simplify \left(y^2\right)^2 using the power of a power property: \left(a^m\right)^n=a^{m\cdot n}. In the expression, m equals 2 and n equals 2.
Simplify the product of conjugate binomials (4y^2+1)(4y^2-1)
Final answer to the exercise
$16y^{4}-1$