$6x\:-\:11\:=\:12x\:+\:7$

$\frac{x^6+2x^4+6x-9}{x^3+3}$

$\lim_{x\to infinity}\left(\frac{x^3+x-\sqrt[3]{1+x^2}}{2x^2+5x}\right)$

$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:58y-34y+x+x$

$\lim\:_{x\to\:\:4}\left(\frac{x-4}{\sqrt{x}-\sqrt{8-x}}\right)$

$\frac{dy}{dx}=\frac{x}{y^2\left(1+x\right)^{\left(\frac{1}{2}\right)}}$

$\left(2x-y^4\right)dx-4y^3\left(x+2y^4\right)dy=0$